在Python中减去一个Hermite级数

要减去一个Hermite级数，请使用Python Numpy中的polynomial.hermite.hermsub()方法。该方法返回一个数组，表示其差异的Hermite级数。返回两个Hermite级数c1-c2的差异。系数的序列从最低阶开始，一直到最高阶，即[1,2,3]表示系列P_0 + 2P_1 + 3P_2。参数c1和c2是按低到高排序的Hermite系列系数的1-D数组。

步骤

首先，导入所需的库−

import numpy as np
from numpy.polynomial import hermite as H

创建Hermite级数系数的一个1-D数组−

c1 = np.array([1,2,3])
c2 = np.array([3,2,1])

显示系数数组−

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型−

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查两个数组的维数−

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查两个数组的形状−

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

要减去一个Hermite级数，请使用Python Numpy中的polynomial.hermite.hermsub()方法−

print("\nResult (difference)....\n",H.hermsub(c1, c2))

例子

import numpy as np
from numpy.polynomial import hermite as H

# 创建Hermite系数的1-D数组
c1 = np.array([1,2,3])
c2 = np.array([3,2,1])

# 显示的系数数组
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# 显示数据类型
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# 检查两个数组的维数
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# 检查两个数组的形状
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# 要减去一个Hermite级数，请使用Python Numpy中的polynomial.hermite.hermsub()方法
# 该方法返回一个数组，表示其差异的Hermite级数
print("\nResult (difference)....\n",H.hermsub(c1, c2))

输出

Array1...
   [1 2 3]

Array2...
   [3 2 1]

Array1 型态...
int64

Array2 型态...
int64

Array1 维度...
1

Array2 维度...
1

Array1 形状...
(3,)

Array2 形状...
(3,)

Result (difference)....
   [-2. 0. 2.]