Python Numpy matrix.I()

在numpy.matrix.I()函数的帮助下，我们可以得到与我们给定矩阵相同大小的乘法逆。

语法: numpy.matrix.I()

返回 : [矩阵对象] 如果自已是非星形的，ret是这样的：ret *自已 ==自已 * ret == np.matrix(np.eye(self[0,:].size) 全部返回 True。返回给定矩阵的乘法逆运算。

代码#1：

# Python program explaining
# numpy.matrix.I() function
  
# importing numpy as geek 
import numpy as geek 
            
mat = geek.matrix('[3, 4; 5, 6]') 
            
# applying matrix.getI() method 
gfg = mat.getI() 
      
print(gfg)

输出 :

[[-3.   2. ]
 [ 2.5 -1.5]]

代码#2：

# Python program explaining
# numpy.matrix.I() function
  
# importing numpy as geek 
import numpy as geek 
            
mat = geek.matrix('[1, 2, 3; 4, 5, 6; 7, 8, 9]') 
            
# applying matrix.getI() method 
gfg = mat.getI() 
      
print(gfg)

输出 :

[[ -4.50359963e+15   9.00719925e+15  -4.50359963e+15]
 [  9.00719925e+15  -1.80143985e+16   9.00719925e+15]
 [ -4.50359963e+15   9.00719925e+15  -4.50359963e+15]]