matplotlib.pyplot.gci()函数

Matplotlib是Python中的一个库，它是NumPy库的数值-数学扩展。Pyplot是一个基于状态的Matplotlib模块接口，该模块提供了一个类似matlab的接口。Pyplot中可以使用的绘图有直线图、轮廓图、直方图、散点图、三维图等。

matplotlib.pyplot.gci()方法

使用matplotlib库pyplot模块中的gci()方法获取当前可着色的artist。

语法:matplotlib.pyplot.gci ()

参数:此方法不接受任何参数。

返回:该方法返回当前可着色的artist。

下面的例子演示了matplotlib.pyplot.gci()函数在matplotlib.pyplot中的作用:

示例1

# Implementation of matplotlib function 
import matplotlib.pyplot as plt 
import numpy as np 
import matplotlib.gridspec as gridspec 
from mpl_toolkits.axes_grid1 import make_axes_locatable 
    
    
plt.close('all') 
arr = np.arange(100).reshape((10, 10)) 
fig = plt.figure(figsize =(4, 4)) 
im = plt.imshow(arr,  
                interpolation ="none", 
                cmap ="plasma") 
    
divider = make_axes_locatable(plt.gca()) 
cax = divider.append_axes("left",  
                          "15 %", 
                          pad ="30 %") 
    
plt.colorbar(im, cax = cax) 
  
print("The current colorable artist is :")
print(plt.gci())
  
fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold") 
  
plt.show()

输出:

matplotlib.pyplot.gci()函数

The current colorable artist is :
AxesImage(50, 44;310x308)

示例2

# Implementation of matplotlib function
import matplotlib.pyplot as plt
from scipy import sin, cos
  
  
fig, ax = plt.subplots(2, 1)
x = [1, 2, 3, 4, 5, 6, 7, 8, 9]
  
y1 = sin(x)
y2 = cos(x)
  
plt.sca(ax[0])
plt.plot(x, y1)
  
plt.sca(ax[1])
plt.plot(x, y2)
  
print("The current colorable artist is :")
print(plt.gci())
  
fig.suptitle('matplotlib.pyplot.gci() function \
Example\n\n', fontweight ="bold") 
  
plt.show()