在Python中用emath计算负输入的平方根

在这篇文章中，我们将介绍如何在Python中使用NumPy用emath计算负输入的平方根。

示例:

Input: [-3,-4]
Output: [0.+1.73205081j 0.+2.j        ]
Explanation: Square root of a negative input.

NumPy.emath.sqrt 方法:

NumPy库中的np.emath.sqrt()方法可以计算复数输入的平方根。与numpy.sqrt.返回NaN不同，负的输入元素会返回一个复数值。

语法: np.emath.sqrt()

参数:

x：类似对象的数组。

返回：out:标量或ndarray。

示例 1:

如果数组包含负的输入值，输出中会返回复数，数组的形状、数据类型和尺寸可以通过.shape、.dtype和.ndim属性找到。

import numpy as np
  
# Creating an array
arr = np.array([-3, -4])
print(array)
  
# shape of the array is
print("Shape of the array is : ",arr.shape)
  
# dimension of the array
print("The dimension of the array is : ",arr.ndim)
  
# Datatype of the array
print("Datatype of our Array is : ",arr.dtype)
  
# computing the square root of negative inputs
print(np.emath.sqrt(arr))

输出:

[-3 -4]
Shape of the array is :  (2,)
The dimension of the array is :  1
Datatype of our Array is :  int64
[0.+1.73205081j 0.+2.j        ]

示例 2:

import numpy as np
  
# Creating an array
array = np.arr([complex(-2, -1),complex(-5, -3)])
print(array)
  
# shape of the array is
print("Shape of the array is : ",arr.shape)
  
# dimension of the array
print("The dimension of the array is : ",arr.ndim)
  
# Datatype of the array
print("Datatype of our Array is : ",arr.dtype)
  
# computing the square root of complex inputs
print(np.emath.sqrt(arr))

输出:

[-2.-1.j -5.-3.j]
Shape of the array is :  (2,)
The dimension of the array is :  1
Datatype of our Array is :  complex128
[0.34356075-1.45534669j 0.64457424-2.32711752j]