Python – Sympy Polygon.intersection()方法
在Sympy中,函数Polygon.intersection()是用来获取给定的多边形和给定的几何实体的交点的。几何实体可以是一个点、线、多边形或其他几何图形。如果多边形和给定的几何实体没有相交的地方,交集可能是空的。但如果存在交集,可以包含单个点或完整的线段。
语法: Polygon.intersection(o)
参数 : Geometry Entity
返回: 分段或交叉点的列表。
示例 #1:
# import Point, Polygon
from sympy import Point, Polygon
# creating points using Point()
p1, p2, p3, p4 = map(Point, [(0, 0), (1, 0), (5, 1), (0, 1)])
p5, p6, p7 = map(Point, [(3, 2), (1, -1), (0, 2)])
# creating polygons using Polygon()
poly1 = Polygon(p1, p2, p3, p4)
poly2 = Polygon(p5, p6, p7)
# using intersection()
isIntersection = poly1.intersection(poly2)
print(isIntersection)
输出:
[Point2D(1/3, 1), Point2D(2/3, 0), Point2D(9/5, 1/5), Point2D(7/3, 1)]
示例 #2:
# import Point, Polygon
from sympy import Point, Polygon
# creating points using Point()
p1, p2, p3, p4 = map(Point, [(0, 0), (1, 0), (5, 1), (0, 1)])
# creating polygon using Polygon()
poly1 = Polygon(p1, p2, p3, p4)
# using intersection()
isIntersection = poly1.intersection(Line(p1, Point(3, 2)))
print(isIntersection)
输出:
[Point2D(0, 0), Point2D(3/2, 1)]