Python Sympy的Line.perpendicular_segment()方法

在Sympy中，函数perpendicular_segment()是用来创建一条从给定的点到给定的线的垂直线段。
含有自己的直线上最近的点。

语法: Line.perpendicular_segment(p)

参数 :
p: Point

返回:
segment: Segment

示例 #1:

# import sympy and Point, Line
from sympy import Point, Line
  
p1, p2, p3 = Point(0, 0), Point(1, 1), Point(0, 2)
l1 = Line(p1, p2)
  
# using perpendicular_segment() method
perpendicularSegment = l1.perpendicular_segment(p3)
  
print(perpendicularSegment)

输出:

Segment2D(Point2D(0, 2), Point2D(1, 1))

示例 #2:

# import sympy and Point3D, Line3D
from sympy import Point3D, Line3D
  
p1, p2, p3 = Point3D(0, 0, 0), Point3D(1, 1, 1), Point3D(0, 2, 0)
ll1 = Line3D(p1, p2)
  
# using perpendicular_segment() method
s1 = l1.perpendicular_segment(p3)
  
perpendicularSegment = l1.perpendicular_segment(p3)
  
print(perpendicularSegment)

输出:

Segment3D(Point3D(0, 2, 0), Point3D(2/3, 2/3, 2/3))