Python Sympy Plane.are_concurrent()方法

在Simpy中，函数Plane.are_concurrent()用于检查给定的平面序列是否是并发的。如果两个或多个平面的交叉点是一条共同的线，那么它们就是并存的。

语法: Plane.are_concurrent()

参数 :
planes: sequence of planes

返回:
True:如果他们是同时进行的，否则False。

示例 #1:

# import sympy, Point3D and Plane
from sympy import Point3D, Plane
  
# using Plane() 
p1 = Plane(Point3D(5, 0, 0), normal_vector =(1, -1, 1))
p2 = Plane(Point3D(0, -2, 0), normal_vector =(3, 1, 1))
  
# using are_concurrent()
areConcurrent = Plane.are_concurrent(p1, p2)
  
print(areConcurrent)

输出:

True

示例 #2:

# import sympy, Point3D and Plane
from sympy import Point3D, Plane
  
# using Plane() 
p1 = Plane(Point3D(5, 0, 0), normal_vector =(1, -1, 1))
p2 = Plane(Point3D(0, -2, 0), normal_vector =(3, 1, 1))
p3 = Plane(Point3D(0, -1, 0), normal_vector =(5, -1, 9))
  
# using are_concurrent()
areConcurrent = Plane.are_concurrent(p1, p2, p3)
  
print(areConcurrent)

输出:

False