Python – Sympy Polygon.distance()方法

在Sympy中，函数Polygon.distance()用来返回给定的多边形与o之间的最短距离。但如果o是另一个多边形，那么，给定的多边形和o必须是凸的。

语法: Polygon.distance(o)

参数 :
o: Point or Polygon

返回: 给定的多边形与o之间的最短距离。

示例 #1:

# import sympy import Point, Polygon
from sympy import Point, Polygon
  
# creating points using Point()
p1, p2, p3, p4 = map(Point, [(0, 2), (0, 0), (1, 0), (1, 2)])
  
# creating polygon using Polygon()
poly = Polygon(p1, p2, p3, p4)
  
# using distance()
shortestDistance = poly.distance(Point(3, 5))
  
print(shortestDistance)

输出:

sqrt(13)

示例 #2:

# import sympy import Point, Polygon, RegularPolygon
from sympy import Point, Polygon, RegularPolygon
  
# creating points using Point()
p1, p2 = map(Point, [(0, 0), (7, 5)])
  
# creating polygon using Polygon() and RegularPolygon()
poly = Polygon(*RegularPolygon(p1, 1, 3).vertices)
  
# using distance()
shortestDistance = poly.distance(p2)
  
print(shortestDistance)

输出:

sqrt(61)