Matplotlib.artist.artist.set_url()

Python matplotlib库的artist模块中的set_url()方法用于设置artist的url。

语法: Artist.set_url(self, url)

参数:该方法只接受一个参数。

url:该参数是包含url的字符串。

Returns:该方法不返回任何值。

下面的例子说明了matplotlib.artist.artistartist.set_url()函数在matplotlib:

示例1

# Implementation of matplotlib function
from matplotlib.artist import Artist 
import numpy as np 
import matplotlib.cm as cm 
import matplotlib.mlab as mlab 
import matplotlib.pyplot as plt
  
    
f, ax = plt.subplots() 
s = ax.scatter([1, 2, 3], [4, 5, 6])
Artist.set_url(s, 'http://www.google.com') 
f.canvas.print_figure('geeks1.svg')
  
f.suptitle("""matplotlib.artist.Artist.set_url()
function Example""", fontweight="bold")
  
plt.show()

输出:

Matplotlib.artist.artist.set_url()

示例2

# Implementation of matplotlib function
from matplotlib.artist import Artist 
import numpy as np 
import matplotlib.cm as cm 
import matplotlib.mlab as mlab 
import matplotlib.pyplot as plt 
    
    
f, ax = plt.subplots() 
delta = 0.025
  
x = y = np.arange(-3.0, 3.0, delta) 
X, Y = np.meshgrid(x, y) 
  
Z1 = np.exp(-X**2 - Y**2) 
Z2 = np.exp(-(X - 1)**2 - (Y - 1)**2) 
Z = (Z1 - Z2) * 2
    
im = ax.imshow(Z, 
               interpolation ='bilinear', 
               cmap = "bone", 
               origin ='lower',  
               extent =[-3, 3, -3, 3]) 
    
Artist.set_url(im, 'https://www.geeksforgeeks.org/') 
f.canvas.print_figure('geeks2.svg')
  
f.suptitle("""matplotlib.artist.Artist.set_url()
function Example""", fontweight="bold")
  
plt.show()

输出:

Matplotlib.artist.artist.set_url()