Matplotlib.patches.PathPatch

Python matplotlib.patches.PathPatch类用于绘制一般的多曲线路径补丁。

语法:

matplotlib.patches.PathPatch(path, **kwargs)

参数:

• path: path是matplotlib.path.path对象。

示例1

import numpy as np
import matplotlib.cm as cm
import matplotlib.pyplot as plt
import matplotlib.cbook as cbook
from matplotlib.path import Path
from matplotlib.patches import PathPatch
  
  
delta = 0.025
x = y = np.arange(-3.0, 3.0, delta)
X, Y = np.meshgrid(x, y)
Z1 = np.exp(-X**2 - Y**2)
Z2 = np.exp(-(X - 1)**2 - (Y - 1)**2)
Z = (Z1 - Z2) * 2
  
path = Path([[0, 1], [1, 0], [0, -1], [-1, 0], [0, 1]])
patch = PathPatch(path, facecolor ='none')
  
fig, ax = plt.subplots()
ax.add_patch(patch)
  
im = ax.imshow(Z, interpolation ='bilinear', cmap = cm.gray,
               origin ='lower', extent =[-3, 3, -3, 3],
               clip_path = patch, clip_on = True)
im.set_clip_path(patch)
  
plt.show()

输出:

示例2

import matplotlib.pyplot as plt 
import numpy as np
from matplotlib.path import Path
from matplotlib.patches import PathPatch
  
  
fig = plt.figure() 
  
ax = fig.add_subplot(111, aspect ='equal') 
path = Path([[0, 0], [0, 1], [1, 0], [0, 0]])
patch = PathPatch(path, facecolor ='none')
ax.add_patch(patch) 
  
Z, Z2 = np.meshgrid(np.linspace(0, 1), np.linspace(0, 1))
  
im = plt.imshow(Z-Z2, 
                interpolation ='bilinear', 
                cmap = plt.cm.RdYlGn,
                origin ='lower',
                extent =[0, 1, 0, 1],
                clip_path = patch,
                clip_on = True)
  
im.set_clip_path(patch)
  
ax.set_xlim((0, 1)) 
ax.set_ylim((0, 1)) 
  
plt.show()

输出: