C程序检查闰年

如果一年是400的倍数，以及一年是4的倍数但不是100的倍数，那么这一年就是一个闰年。

比如说。

2000年是闰年
2022年不是闰年
2019年不是闰年

检查闰年的C程序

以下是伪代码。

if year is divisible by 400 then is_leap_year
else if year is divisible by 100 then not_leap_year
else if year is divisible by 4 then is_leap_year
else not_leap_year

// C program to check if a given 
// year is leap year or not
#include <stdio.h>
#include <stdbool.h>
  
bool checkYear(int year)
{
    // If a year is multiple of 400, 
    // then it is a leap year
    if (year % 400 == 0)
        return true;
  
    // Else If a year is multiple of 100,
    // then it is not a leap year
    if (year % 100 == 0)
        return false;
  
    // Else If a year is multiple of 4,
    // then it is a leap year
    if (year % 4 == 0)
        return true;
    return false;
}
  
// Driver code
int main()
{
    int year = 2000;
  
    checkYear(year)? printf("Leap Year"):
                     printf("Not a Leap Year");
    return 0;
}

输出

Leap Year

Time Complexity: O(1)
Auxiliary Space: O(1)

如何在一行中写出上述代码？

检查闰年的C程序

// One line C program to check if a 
// given year is leap year or not
#include <stdio.h>
#include <stdbool.h>
  
bool checkYear(int year)
{
// Return true if year is a multiple
// of 4 and not multiple of 100.
// OR year is multiple of 400.
return (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0));
}
  
// Driver code
int main()
{
    int year = 2000;
  
    checkYear(year)? printf("Leap Year"):printf("Not a Leap Year");
    
    return 0;
}

输出