C程序二进制字符串求和

给定两个二进制字符串，我们必须以二进制形式返回其总和。

方法： 我们将从两个字符串的最后一个开始，按照二进制加法进行加法，如果我们得到任何携带，我们将把它加到下一个数字。

输入:

11 + 11

输出:

// C Program to Add 2 Binary Strings
// and Print their Binary Sum
#include <stdio.h>
#include <string.h>
 
// Function to add two Binary Strings
void sum(char b1[], char b2[], int l1, int l2)
{
    int carry = 0, temp, num1, num2, i;
    char result[100];
 
    result[l1 + 1] = '\0';
 
    // This loop will add Both Strings till
    // second have characters in it.
    while (l2 > 0) {
        num1 = b1[l1 - 1] - '0';
        num2 = b2[l2 - 1] - '0';
        temp = num1 + num2 + carry;
        if (temp >= 2) {
            carry = 1;
            temp = temp % 2;
        }
        result[l1] = temp + '0';
        l1--;
        l2--;
    }
 
    // This loop will add leftover
    // characters of first Strings.
    while (l1 - 1 >= 0) {
        temp = b1[l1 - 1] + carry - '0';
        if (temp >= 2) {
            carry = 1;
            temp = temp % 2;
        }
        result[l1] = temp + '0';
        l1--;
    }
 
    // Add last carry to result string
    if (carry) {
        result[0] = '1';
    }
    else {
        // if there is no carry then we will shift
        // each character by one place in left side.
        for (i = 0; i < strlen(result) - 1; i++) {
            result[i] = result[i + 1];
        }
        result[strlen(result) - 1] = '\0';
    }
 
    // printing result
    printf("%s + %s = %s\n", b1, b2, result);
}
 
// Driver code
int main()
{
    char b1[100] = "11", b2[100] = "11";
    int l1, l2;
 
    printf("Enter binary number 1: ");
    printf("%s \n", b1);
    printf("Enter binary number 2: ");
    printf("%s \n", b2);
    l1 = strlen(b1);
    l2 = strlen(b2);
 
    // calling function to add strings
    if (l1 > l2) {
        sum(b1, b2, l1, l2);
    }
    else {
        sum(b2, b1, l2, l1);
    }
 
    return 0;
}

输出

Enter binary number 1: 11 
Enter binary number 2: 11 
11 + 11 = 110

使用while循环

#include <stdio.h>
 
int main() {
 
      long binary1=10000, binary2=10000;
    int i = 0, remainder = 0, sum[20];
  
    while (binary1 != 0 || binary2 != 0)
    {
        sum[i++] =(binary1 % 10 + binary2 % 10 + remainder) % 2;
        remainder =(binary1 % 10 + binary2 % 10 + remainder) / 2;
        binary1 = binary1 / 10;
        binary2 = binary2 / 10;
    }
    if (remainder != 0)
        sum[i++] = remainder;
    --i;
    printf("Sum of two binary numbers: ");
    while (i >= 0)
        printf("%d", sum[i--]);
    return 0;
}

输出