SymPy Python中的Polyhedron.pgroup()

Polyhedron.pgroup() : pgroup()是一个Sympy Python库函数，用于返回多面体的排列组合。

语法 : sympy.combinatorics.Polyhedrons.Polyhedron.pgroup()

返回：多面体的排列组合。

代码 #1 : pgroup() 示例 – 四面体

# Python code explaining
# SymPy.Polyhedron.pgroup()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.pgroup()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - pgroup form : ", a.pgroup)
  
a.rotate(0)
print ("\nPolyhedron - pgroup form : ", a.pgroup)

输出 :

Polyhedron – pgroup form : PermutationGroup([
(1 2 3),
(3)(0 1 2),
(0 3 2),
(0 3 1),
(0 1)(2 3),
(0 2)(1 3),
(0 3)(1 2)])

Polyhedron – pgroup form : PermutationGroup([
(1 2 3),
(3)(0 1 2),
(0 3 2),
(0 3 1),
(0 1)(2 3),
(0 2)(1 3),
(0 3)(1 2)])

代码 #2 : pgroup() 示例 – 八面体

# Python code explaining
# SymPy.Polyhedron.pgroup()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.pgroup()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - pgroup form : ", a.pgroup)
  
a.rotate(0)
print ("\nPolyhedron - pgroup form : ", a.pgroup)

输出 :

Polyhedron – pgroup form : PermutationGroup([
(5)(1 2 3 4),
(0 4 5 2),
(0 1 5 3),
(0 1)(2 4)(3 5),
(0 2)(1 3)(4 5),
(0 3)(1 5)(2 4),
(0 4)(1 3)(2 5),
(0 5)(1 4)(2 3),
(0 5)(1 2)(3 4),
(0 4 1)(2 3 5),
(0 1 2)(3 4 5),
(0 2 3)(1 5 4),
(0 4 3)(1 5 2)])

Polyhedron – pgroup form : PermutationGroup([
(5)(1 2 3 4),
(0 4 5 2),
(0 1 5 3),
(0 1)(2 4)(3 5),
(0 2)(1 3)(4 5),
(0 3)(1 5)(2 4),
(0 4)(1 3)(2 5),
(0 5)(1 4)(2 3),
(0 5)(1 2)(3 4),
(0 4 1)(2 3 5),
(0 1 2)(3 4 5),
(0 2 3)(1 5 4),
(0 4 3)(1 5 2)])