SymPy Python中的Polyhedron.faces()

Polyhedron.faces() : faces()是一个Sympy Python库函数，用于返回多面体的面。

语法 : sympy.combinatorics.Polyhedrons.Polyhedron.faces()

返回：多面体的面。

代码 #1 : faces() 示例 – 四面体

# Python code explaining
# SymPy.Polyhedron.faces()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.faces()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - faces form : ", a.faces)
  
a.rotate(0)
print ("\nPolyhedron - faces form : ", a.faces)

输出 :

Polyhedron – faces form : {(0, 1, 2), (0, 1, 3), (0, 2, 3), (1, 2, 3)}

Polyhedron – faces form : {(0, 1, 2), (0, 1, 3), (0, 2, 3), (1, 2, 3)}

代码 #2 : faces() 示例 – 八面体

# Python code explaining
# SymPy.Polyhedron.faces()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.faces()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - faces form : ", a.faces)
  
a.rotate(0)
print ("\nPolyhedron - faces form : ", a.faces)

输出 :

Polyhedron – faces form : {(0, 1, 2), (0, 1, 4), (0, 2, 3), (0, 3, 4), (1, 2, 5), (1, 4, 5), (2, 3, 5), (3, 4, 5)}

Polyhedron – faces form : {(0, 1, 2), (0, 1, 4), (0, 2, 3), (0, 3, 4), (1, 2, 5), (1, 4, 5), (2, 3, 5), (3, 4, 5)}