极客教程Python Pandas – 从TimeDeltaIndex中提取每个元素的秒数
要从TimeDeltaIndex对象中提取每个元素的秒数，请使用 TimedeltaIndex.seconds 属性。
首先，导入所需的库−
import pandas as pd
创建一个TimeDeltaIndex对象。 我们还使用’data’参数设置了类似于时间差的数据−
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
显示TimedeltaIndex−
print("TimedeltaIndex...\n", tdIndex)
显示TimeDeltaIndex的每个元素的秒数−
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)
示例
以下是代码−
import pandas as pd
# 创建TimeDeltaIndex对象
# 我们还使用'data'参数设置了类似于时间差的数据
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 35s 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
# 显示TimedeltaIndex
print("TimeDeltaIndex...\n", tdIndex)
# 显示TimeDeltaIndex的每个元素的秒数
print("\nThe number of seconds from the TimeDeltaIndex object...\n", tdIndex.seconds)
# 返回TimeDelta组件的数据帧
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
输出
这将产生以下代码−
TimeDeltaIndex...
TimedeltaIndex(['10 days 05:02:35.000003010', '0 days 22:39:19.999999',
'2 days 07:08:02.000045', '0 days 21:15:45.999999'],
dtype='timedelta64[ns]', freq=None)
The number of seconds from the TimeDeltaIndex object...
Int64Index([18155, 81559, 25682, 76545], dtype='int64')
The Dataframe of the components of TimeDeltas...
days hours minutes seconds milliseconds microseconds nanoseconds
0 10 5 2 35 0 3 10
1 0 22 39 19 999 999 0
2 2 7 8 2 0 45 0
3 0 21 15 45 999 999 0