Python Pandas – 从TimeDeltaIndex创建Series
使用 to_series() 方法在Pandas中从TimeDeltaIndex创建Series。
首先,导入所需的库 −
import pandas as pd
创建一个TimeDeltaIndex对象。我们使用“data”参数设置timedelta-like数据 −
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
将TimeDeltaIndex转换为Series −
print("\nTimeDeltaIndex to series...\n", tdIndex.to_series())
示例
以下是代码 –
import pandas as pd
# 创建一个TimeDeltaIndex对象
# 我们使用“data”参数设置timedelta-like数据
tdIndex = pd.TimedeltaIndex(data =['10 day 5h 2 min 3us 10ns', '+22:39:19.999999',
'2 day 4h 03:08:02.000045', '+21:15:45.999999'])
# 显示TimedeltaIndex
print("TimedeltaIndex...\n", tdIndex)
# 返回TimeDeltas的组件的数据框
print("\nThe Dataframe of the components of TimeDeltas...\n", tdIndex.components)
# 将TimeDeltaIndex作为对象ndarray返回
print("\nReturn TimeDeltaIndex as object ndarray of datetime.datetime objects...\n",
tdIndex.to_pytimedelta())
# 将TimeDeltaIndex转换为Series
print("\nTimeDeltaIndex to series...\n", tdIndex.to_series())
输出
这将产生以下代码 –
TimedeltaIndex...
TimedeltaIndex(['10 days 05:02:00.000003010', '0 days 22:39:19.999999',
'2 days 07:08:02.000045', '0 days 21:15:45.999999'],
dtype='timedelta64[ns]', freq=None)
时间戳组件数据框...
days hours minutes seconds milliseconds microseconds nanoseconds
0 10 5 2 0 0 3 10
1 0 22 39 19 999 999 0
2 2 7 8 2 0 45 0
3 0 21 15 45 999 999 0
将TimeDeltaIndex作为对象ndarray返回datetime.datetime对象...
[datetime.timedelta(days=10, seconds=18120, microseconds=3)
datetime.timedelta(seconds=81559, microseconds=999999)
datetime.timedelta(days=2, seconds=25682, microseconds=45)
datetime.timedelta(seconds=76545, microseconds=999999)]
TimeDeltaIndex to series...
10 days 05:02:00.000003010 10 days 05:02:00.000003010
0 days 22:39:19.999999 0 days 22:39:19.999999
2 days 07:08:02.000045 2 days 07:08:02.000045
0 days 21:15:45.999999 0 days 21:15:45.999999
dtype: timedelta64[ns]