比较Pandas DataFrame中的特定时间戳 ŌĆō Python
要比较特定的时间戳,请在方括号中使用索引号。首先,导入所需的库-
import pandas as pd
创建一个具有3列的DataFrame。我们有两列包含时间戳的日期列-
dataFrame = pd.DataFrame(
{
"Car": ["Audi", "Lexus", "Tesla", "Mercedes", "BMW"],
"Date_of_Purchase": [
pd.Timestamp("2021-06-10"),
pd.Timestamp("2021-07-11"),
pd.Timestamp("2021-06-25"),
pd.Timestamp("2021-06-29"),
pd.Timestamp("2021-03-20"),
],
"Date_of_Service": [
pd.Timestamp("2021-11-05"),
pd.Timestamp("2021-12-03"),
pd.Timestamp("2021-10-30"),
pd.Timestamp("2021-11-29"),
pd.Timestamp("2021-08-20"),
]
})
查找特定的时间戳,例如1到3行-
timestamp1_diff = abs(dataFrame['Date_of_Purchase'][0]-dataFrame['Date_of_Service'][0])
timestamp2_diff = abs(dataFrame['Date_of_Purchase'][1]-dataFrame['Date_of_Service'][1])
timestamp3_diff = abs(dataFrame['Date_of_Purchase'][2]-dataFrame['Date_of_Service'][2])
示例
以下是代码-
import pandas as pd
#创建3列的dataframe
dataFrame = pd.DataFrame(
{
"Car": ["Audi", "Lexus", "Tesla", "Mercedes", "BMW"],
"Date_of_Purchase": [
pd.Timestamp("2021-06-10"),
pd.Timestamp("2021-07-11"),
pd.Timestamp("2021-06-25"),
pd.Timestamp("2021-06-29"),
pd.Timestamp("2021-03-20"),
],
"Date_of_Service": [
pd.Timestamp("2021-11-05"),
pd.Timestamp("2021-12-03"),
pd.Timestamp("2021-10-30"),
pd.Timestamp("2021-11-29"),
pd.Timestamp("2021-08-20"),
]
})
print"DataFrame...\n", dataFrame
#比较特定的时间戳
timestamp1_diff = abs(dataFrame['Date_of_Purchase'][0]-dataFrame['Date_of_Service'][0])
timestamp2_diff = abs(dataFrame['Date_of_Purchase'][1]-dataFrame['Date_of_Service'][1])
timestamp3_diff = abs(dataFrame['Date_of_Purchase'][2]-dataFrame['Date_of_Service'][2])
print"\n Car 1日期购买和服务之间的差异\n",timestamp1_diff
print"\n Car 2日期购买和服务之间的差异\n",timestamp2_diff
print"\n Car 3日期购买和服务之间的差异\n",timestamp3_diff
输出
将产生以下输出-
DataFrame...
Car Date_of_Purchase Date_of_Service
0 Audi 2021-06-10 2021-11-05
1 Lexus 2021-07-11 2021-12-03
2 Tesla 2021-06-25 2021-10-30
3 Mercedes 2021-06-29 2021-11-29
4 BMW 2021-03-20 2021-08-20
差异 between Car 1日期购买和服务之间
148 days 00:00:00
差异 between Car 2日期购买和服务之间
145 days 00:00:00
差异 between Car 3日期购买和服务之间
127 days 00:00:00