Python numpy.tile()

numpy.tile()函数通过重复数组-‘arr’来构造一个新的数组，我们想要重复的次数为repetitions。结果数组的尺寸是max(arr.ndim, repetitions)，其中，repetitions是重复的长度。如果arr.ndim > repetitions，reps将通过预置1而被提升到arr.ndim。如果arr.ndim < repetitions，reps通过预置新轴被提升到arr.ndim。

语法 :

numpy.tile(arr, repetitions)

参数 :

array : [array_like]输入阵列。
repetitions :Arr在每个轴上的重复次数。

返回 :

一个带有重复数组的数组–Arr按照d，我们想重复Arr的次数。

代码 1 :

# Python Program illustrating
# numpy.tile()
 
import numpy as geek
 
#Working on 1D
arr = geek.arange(5)
print("arr : \n", arr)
 
repetitions = 2
print("Repeating arr 2 times : \n", geek.tile(arr, repetitions))
 
repetitions = 3
print("\nRepeating arr 3 times : \n", geek.tile(arr, repetitions))
# [0 1 2 ..., 2 3 4] means [0 1 2 3 4 0 1 2 3 4 0 1 2 3 4]
# since it was long output, so it uses [ ... ]

输出 :

arr : 
 [0 1 2 3 4]
Repeating arr 2 times : 
 [0 1 2 3 4 0 1 2 3 4]

Repeating arr 3 times : 
 [0 1 2 ..., 2 3 4]

代码 2 :

# Python Program illustrating
# numpy.tile()
 
import numpy as geek
 
arr = geek.arange(3)
print("arr : \n", arr)
 
a = 2 
b = 2 
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
 
a = 3 
b = 2  
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
 
a = 2
b = 3 
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)

输出 :

arr : 
 [0 1 2]

Repeating arr : 
 [[0 1 2 0 1 2]
 [0 1 2 0 1 2]]
arr Shape : 
 (2, 6)

Repeating arr : 
 [[0 1 2 0 1 2]
 [0 1 2 0 1 2]
 [0 1 2 0 1 2]]
arr Shape : 
 (3, 6)

Repeating arr : 
 [[0 1 2 ..., 0 1 2]
 [0 1 2 ..., 0 1 2]]
arr Shape : 
 (2, 9)

代码3:(重复== arr.ndim) == 0

# Python Program illustrating
# numpy.tile()
 
import numpy as geek
 
arr = geek.arange(4).reshape(2, 2)
print("arr : \n", arr)
 
a = 2 
b = 1 
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
 
a = 3 
b = 2  
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
 
a = 2
b = 3 
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)

输出 :

arr : 
 [[0 1]
 [2 3]]

Repeating arr : 
 [[0 1]
 [2 3]
 [0 1]
 [2 3]]
arr Shape : 
 (4, 2)

Repeating arr : 
 [[0 1 0 1]
 [2 3 2 3]
 [0 1 0 1]
 [2 3 2 3]
 [0 1 0 1]
 [2 3 2 3]]
arr Shape : 
 (6, 4)

Repeating arr : 
 [[0 1 0 1 0 1]
 [2 3 2 3 2 3]
 [0 1 0 1 0 1]
 [2 3 2 3 2 3]]
arr Shape : 
 (4, 6)