Java 实例 检查 Armstrong 数

xy..z = xn + yn+.....+ zn

370 = 33 + 73 + o3
         = 27 + 343 + 0
         = 370

public class JavaExample {

    public static void main(String[] args) {

        int num = 370, number, temp, total = 0;

        number = num;
        while (number != 0)
        {
            temp = number % 10;
            total = total + temp*temp*temp;
            number /= 10;
        }

        if(total == num)
            System.out.println(num + " is an Armstrong number");
        else
            System.out.println(num + " is not an Armstrong number");
    }
}

370 is an Armstrong number

for( ;number!=0;number /= 10){
    temp = number % 10;
    total = total + temp*temp*temp;
}

import java.util.Scanner;
public class JavaExample {

    public static void main(String[] args) {

        int num, number, temp, total = 0;
        System.out.println("Ënter 3 Digit Number");
        Scanner scanner = new Scanner(System.in);
        num = scanner.nextInt();
        scanner.close();
        number = num;

        for( ;number!=0;number /= 10)
        {
            temp = number % 10;
            total = total + temp*temp*temp;
        }

        if(total == num)
            System.out.println(num + " is an Armstrong number");
        else
            System.out.println(num + " is not an Armstrong number");
    }
}

Ënter 3 Digit Number
371
371 is an Armstrong number