Python中的SymPy Permutation.order()

Permutation.order() : order()是一个sympy Python库函数，用于计算一个排列组合的顺序。当排列组合被提升到其顺序的幂，那么，在这种情况下，顺序就等于相同的排列组合。

语法 : sympy.combinatorics.permutations.Permutation.order()

返回：排列组合的顺序

代码 #1 : order() 示例

# Python code explaining
# SymPy.Permutation.order()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.order() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - order form : ", a.order())
print ("Permutation b - order form : ", b.order())

输出 :

Permutation a – order form : 2
Permutation b – order form : 6

代码#2：order()示例–二维互换法

# Python code explaining
# SymPy.Permutation.order()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.order() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - order form : ", a.order())