Python中的SymPy Permutation.is_Identity()

Permutation.is_Identity() : is_Identity() 是一个 Sympy Python 库函数，用于检查 Permutation 是否是一个身份置换。

语法 : sympy.combinatorics.permutations.Permutation.is_Identity()

返回：真 – 如果他的排列组合是一个身份排列组合；否则为假。

代码 #1 : is_Identity() 示例

# Python code explaining
# SymPy.Permutation.is_Identity()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
print ("Permutation a - is_Identity form : ", a.is_Identity)
print ("Permutation b - is_Identity form : ", b.is_Identity)

输出 :

Permutation a – is_Identity form : False
Permutation b – is_Identity form : False

代码 #2 : is_Identity() 示例 – 二维排列

# Python code explaining
# SymPy.Permutation.is_Identity()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - is_Identity form : ", a.is_Identity)