Python中的SymPy Permutation.is_odd()

Permutation.is_odd() : is_odd()是一个sympy Python库函数，用于检查排列组合是否为奇数。

语法 : sympy.combinatorics.permutations.Permutation.is_odd()

返回：真 – 如果排列组合是奇数；否则为假

代码 #1 : is_odd() 示例

# Python code explaining
# SymPy.Permutation.is_odd()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_odd() method 
  
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
  
b = Permutation([1, 3, 5, 4, 2, 0])
  
  
print ("Permutation a - is_odd form : ", a.is_odd)
print ("Permutation b - is_odd form : ", b.is_odd)

输出 :

Permutation a – is_odd form : False
Permutation b – is_odd form : True

代码#2：is_odd()示例–二维排列组合

# Python code explaining
# SymPy.Permutation.is_odd()
  
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
  
# Using from sympy.combinatorics.permutations.Permutation.is_odd() method 
  
# creating Permutation
a = Permutation([[2, 4, 0], 
                 [3, 1, 2],
                 [1, 5, 6]])
  
  
print ("Permutation a - is_odd form : ", a.is_odd)