Python Pandas – 从 IntervalIndex 中获取中点

Python Pandas – 从 IntervalIndex 中获取中点

要从 Pandas 的 IntervalIndex 中获取中点,请使用 interval.mid 属性。首先,导入所需的库 –

import pandas as pd

创建 IntervalIndex –

interval = pd.IntervalIndex.from_arrays([10, 15, 20], [20, 25, 30])

显示间隔 –

print("IntervalIndex...\n",interval)

返回间隔的中点 –

print("\nThe midpoint for the Interval...\n",interval.mid)

示例

以下是代码 –

import pandas as pd

# 创建 IntervalIndex
interval = pd.IntervalIndex.from_arrays([10, 15, 20], [20, 25, 30])

# 显示间隔
print("IntervalIndex...\n",interval)

# 显示间隔长度
print("\nIntervalIndex length...\n",interval.length)

# 检查 IntervalIndex 的左侧、右侧、两侧或无是否关闭
print("\nChecking for the type of IntervalIndex...\n",interval.closed)

# 左边界
print("\nThe left bound for the IntervalIndex...\n",interval.left)

# 右边界
print("\nThe right bound for the IntervalIndex...\n",interval.right)

# 返回间隔的中点
print("\nThe midpoint for the Interval...\n",interval.mid)

输出

这将产生以下输出 –

IntervalIndex...
IntervalIndex([(10, 20], (15, 25], (20, 30]], dtype='interval[int64, right]')

IntervalIndex length...
Int64Index([10, 10, 10], dtype='int64')

Checking for the type of IntervalIndex...
right

The left bound for the IntervalIndex...
Int64Index([10, 15, 20], dtype='int64')

The right bound for the IntervalIndex...
Int64Index([20, 25, 30], dtype='int64')

The midpoint for the Interval...
Float64Index([15.0, 20.0, 25.0], dtype='float64')

Python教程

Java教程

Web教程

数据库教程

图形图像教程

大数据教程

开发工具教程

计算机教程