Python numpy.count()

numpy.core.defchararray.count(arr, substring, start=0, end=None) :计算指定范围内子字符串的非重叠出现次数。

参数:
arr :要搜索的数组类或字符串。
substring :要搜索的子串。
start，end。[int, optional] 要搜索的范围。

返回值 :一个整数数组，包含子串的非重叠出现次数。

代码 #1:

# Python Program illustrating 
# numpy.char.count() method 
  
import numpy as np 
  
# 2D array 
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
  
print ("arr : ", arr)
  
print ("Count of 'tt'", np.char.count(arr, 'tt'))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 0))
print ("Count of 'tt'", np.char.count(arr, 'tt', start = 8))

输出:

arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
Count of 'tt' [2 2 1 0]
Count of 'tt' [2 2 1 0]
Count of 'tt' [1 2 1 0]

代码 #2:

# Python Program illustrating 
# numpy.char.count() method 
import numpy as np 
  
# 2D array 
arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
  
print ("arr : ", arr)
  
print ("Count of 'Aa'", np.char.count(arr, 'Aa'))
print ("Count of 'Aa'", np.char.count(arr, 'Aa', start = 8))

输出:

arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']

Count of 'Aa' [1 1 1 1]
Count of 'Aa' [1 0 0 0]