Java StrictMath exp()方法

java.lang.StrictMath.exp() 是Java中的一个内置方法，用于返回一个提升到指定双倍值的欧拉数。它产生了三个特殊的结果。

• 当给定的参数是正无穷大时，其结果是正无穷大。
• 当参数是负无穷大时，结果是正零。
• 当给定参数为NaN时，结果为NaN。

语法:

public static double exp( _double num_ )

参数： 该方法接受一个参数 num ，该参数为双倍类型，是将e提高到的指数。
返回值： 该方法返回值e^num，其中e是自然对数的基数。
示例 。

Input: num = 7
Output: 1096.6331584284585

Input: num = (1.0 / 0.0)
Output: Infinity

下面的程序说明了java.lang.StrictMath.exp()方法：
程序1

// Java program to illustrate the
// java.lang.StrictMath.exp()
import java.lang.*;
 
public class Geeks {
 
    public static void main(String[] args)
    {
 
        double num1 = 0.0, num2 = (1.0 / 0.0);
        double num3 = 4;
 
        // Returns Euler's number e raised to the given power
        double expValue = StrictMath.exp(num1);
        System.out.println("The exp value of "+
                         num1+" = " + expValue);
 
        expValue = StrictMath.exp(num2);
        System.out.println("The exp value of "+
                         num2+" = " + expValue);
 
        expValue = StrictMath.exp(num3);
        System.out.println("The exp value of "+
                         num3+" = " + expValue);    }
}

输出

The exp value of 0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 4.0 = 54.598150033144236

程序2

// Java program to illustrate the
// java.lang.StrictMath.exp()
import java.lang.*;
 
public class Geeks {
 
    public static void main(String[] args)
    {
 
        double num1 = -0.0, num2 = (1.0 / 0.0);
        double num3 = 14;
 
        // Returns Euler's number e raised to the given power
        double expValue = StrictMath.exp(num1);
        System.out.println("The exp value of "+
                         num1+" = " + expValue);
 
        expValue = StrictMath.exp(num2);
        System.out.println("The exp value of "+
                         num2+" = " + expValue);
 
        expValue = StrictMath.exp(num3);
        System.out.println("The exp value of "+
                         num3+" = " + expValue);
    }
}

输出

The exp value of -0.0 = 1.0
The exp value of Infinity = Infinity
The exp value of 14.0 = 1202604.2841647768