SymPy Python中的Polyhedron.cyclic_form()

Polyhedron.cyclic_form() : cyclic_form()是一个Sympy Python库函数，它以循环符号返回角的索引。

语法 : sympy.combinatorics.Polyhedrons.Polyhedron.cyclic_form()

返回 :
循环记号中的角的指数

代码 #1 : cyclic_form() 示例 – 四面体

# Python code explaining
# SymPy.Polyhedron.cyclic_form()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form()
  
# Creating Polyhedron
a = tetrahedron.copy()
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form)
  
a.rotate(0)
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)

输出 :

Polyhedron – cyclic_form form : []

Polyhedron – cyclic_form form : [[1, 2, 3]]

代码 #2 : cyclic_form() 示例 – 八面体

# Python code explaining
# SymPy.Polyhedron.cyclic_form()
  
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron
  
# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.cyclic_form()
  
# Creating Polyhedron
a = octahedron.copy()
  
print ("Polyhedron - cyclic_form form : ", a.cyclic_form)
  
a.rotate(0)
print ("\nPolyhedron - cyclic_form form : ", a.cyclic_form)