Python SymPy Permutation.ascents()方法
Permutation.ascents() : ascents()是一个sympy Python库函数,用于返回permutation中ascents的位置。
上升是指a[i]< a[i+1]的元素。
语法 : sympy.combinatorics.permutations.Permutation.ascents()
返回:在排列组合中的上升位置
代码 #1 : ascents() 示例
# Python code explaining
# SymPy.ascents()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.ascents() method
# creating Permutation
a = Permutation([[2, 0], [3, 1]])
b = Permutation([1, 3, 5, 4, 2, 0])
print ("Permutation a - ascents form : ", a.ascents())
print ("Permutation b - ascents form : ", b.ascents())
输出 :
Permutation a – ascents form : [0, 2]
Permutation b – ascents form : [0, 1]
代码#2:ascents()示例–二维排布
# Python code explaining
# SymPy.ascents()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.ascents() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
print ("Permutation a - ascents form : ", a.ascents())
输出 :
Permutation a – ascents form : [1, 2, 4]