Ruby Date gregorian?函数
Date#gregorian?() 是Date类的一个方法,用于检查日期是否在日历改革的当天或之后。
语法。Date.gregorian?()
参数。日期值
返回:true – 如果日期是在日历改革的当天或之后,否则返回false。
例子 #1 :
# Ruby code for Date.gregorian?() method
# loading date
require 'date'
# declaring Date
a = Date.new(2019, 1, 1)
# declaring Date
b = Date.jd(2452004)
# declaring Date
c = Date.ordinal(2019, 12)
# Date
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
# gregorian? form
puts "Date a gregorian? form : #{a.gregorian?}\n\n"
puts "Date b gregorian? form : #{b.gregorian?}\n\n"
puts "Date c gregorian? form : #{c.gregorian?}\n\n"
输出:
Date a : 2019-01-01
Date b : 2001-04-04
Date c : 2019-01-12
Date a gregorian? form : true
Date b gregorian? form : true
Date c gregorian? form : true
例子 #2 :
# Ruby code for Date.gregorian?() method
# loading date
require 'date'
# declaring Date
a = Date.parse('2019-01-01')
# declaring Date
b = Date.strptime('03-12-2019', '%d-%m-%Y')
# declaring Date
c = Date.commercial(2019, 5, 6)
# Date
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
# gregorian? form
puts "Date a gregorian? form : #{a.gregorian?}\n\n"
puts "Date b gregorian? form : #{b.gregorian?}\n\n"
puts "Date c gregorian? form : #{c.gregorian?}\n\n"
输出:
Date a : 2019-01-01
Date b : 2019-12-03
Date c : 2019-02-02
Date a gregorian? form : true
Date b gregorian? form : true
Date c gregorian? form : true