Ruby Date amjd()函数
Date#amjd() : amjd() 是Date类的一个方法,用于返回天文上修正的朱利安日数字。
语法: Date.amjd()
参数: Date值
返回: 天文上修改后的朱利安日数字。
例子 #1 :
Ruby 1=1
输出:
Date a : 2019-01-01
Date b : 2001-04-04
Date c : 2019-01-12
Date a amjd form : 58484/1
Date b amjd form : 52003/1
Date c amjd form : 58495/1
例子 #2 :
# Ruby code for Date.amjd() method
# loading date
require 'date'
# declaring Date
a = Date.parse('2019-01-01')
# declaring Date
b = Date.strptime('03-12-2019', '%d-%m-%Y')
# declaring Date
c = Date.commercial(2019, 5, 6)
# Date
puts "Date a : #{a}\n\n"
puts "Date b : #{b}\n\n"
puts "Date c : #{c}\n\n\n\n"
# amjd form
puts "Date a amjd form : #{a.amjd}\n\n"
puts "Date b amjd form : #{b.amjd}\n\n"
puts "Date c amjd form : #{c.amjd}\n\n"
输出:
Date a : 2019-01-01
Date b : 2019-12-03
Date c : 2019-02-02
Date a amjd form : 58484/1
Date b amjd form : 58820/1
Date c amjd form : 58516/1