MySQL 如何搜索以A开头的名字

使用LIKE，如下所示−

select *from yourTableName where yourColumnName LIKE 'A%';

让我们首先创建一个表−

mysql> create table DemoTable
   (
   StudentName varchar(100)
   );
Query OK, 0 rows affected (0.66 sec)

现在，您可以使用insert命令在表中插入一些记录−

mysql> insert into DemoTable values('John Smith');
Query OK, 1 row affected (0.21 sec)
mysql> insert into DemoTable values('Adam Smith');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Aaron Taylor');
Query OK, 1 row affected (0.43 sec)
mysql> insert into DemoTable values('Chris Brown');
Query OK, 1 row affected (0.27 sec)

使用select语句显示表中的所有记录−

mysql> select *from DemoTable;

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输出

+--------------+
| StudentName  |
+--------------+
| John Smith   |
| Adam Smith   |
| Aaron Taylor |
| Chris Brown  |
+--------------+
4 rows in set (0.00 sec)

以下是在MySQL中搜索以A开头的名字的查询−

mysql> select *from DemoTable where StudentName LIKE 'A%';

输出

+--------------+
| StudentName  |
+--------------+
| Adam Smith   |
| Aaron Taylor |
+--------------+
2 rows in set (0.00 sec)