Java Integer toOctalString()方法
八进制是以8为基数的数字系统,在运算中使用数字0到7。八进制广泛用于PDP-8等系统的计算,IBM大型机采用12位、24位或36位字。
Java.lang.Integer.toOctalString()方法是Java中的一个内置函数,用于返回整数参数的字符串表示,作为基数8的无符号整数。
语法
public static String toOctalString(int num)
参数: 该方法接受一个整数类型的参数 num ,该参数需要转换为字符串。
返回值: 该函数返回整数参数的字符串表示,为基数8的无符号整数。
示例
Consider an integer a = 86
Octal output = 126
Consider an integer a = 186
Octal output = 272
下面的程序说明了Integer.toOctalString()方法的工作情况:
程序1: 对于正整数。
// Java program to demonstrate working
// of Integer.toOctalString() method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
int a = 527;
System.out.println("Integral Number = " + a);
// returns the string representation of the unsigned int value
// represented by the argument in octal (base 8)
System.out.println("Octal Number = " + Integer.toOctalString(a));
}
}
输出
Integral Number = 527
Octal Number = 1017
程序2: 对于负整数。
// Java program to demonstrate working
// of Integer.toOctalString() method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
int a = -51;
System.out.println("Integral Number = " + a);
// Returns the string representation of the unsigned int value
// in octal (base 8)
System.out.println("Octal Number = " + Integer.toOctalString(a));
}
}
输出
Integral Number = -51
Octal Number = 37777777715
程序3: 对于十进制数值或字符串:
注意: 每当十进制数字或字符串作为参数被传递时,它将返回一个错误信息,导致 类型不兼容。
// Java program to demonstrate working
// of Integer.toOctalString() method
import java.lang.*;
public class Geeks {
public static void main(String[] args)
{
double a = 18.71;
// Returns the string representation of the unsigned int value
// in octal (base 8)
System.out.println("Octal output = " + Integer.toOctalString(a));
String b = "63";
// Returns the string representation of the unsigned int value
// in octal (base 8)
System.out.println("Octal output = " + Integer.toOctalString(a));
}
}
输出
prog.java:15: error: incompatible types: possible lossy conversion from double to int
System.out.println("Octal output = " + Integer.toOctalString(a));
^
prog.java:21: error: incompatible types: possible lossy conversion from double to int
System.out.println("Octal output = " + Integer.toOctalString(a));
^
Note: Some messages have been simplified; recompile with -Xdiags:verbose to get full output
2 errors