Java LinkedHashSet removeAll()方法及示例
java.util.LinkedHashSet 类的 removeAll() 方法是用来从这个集合中删除所有包含在指定集合中的元素。
语法
public boolean removeAll(Collection c)
参数: 该方法接受集合c作为参数,包含要从这个集合中删除的元素。
返回值: 如果这个集合在调用后发生了变化,该方法返回true。
异常: 如果这个集合包含一个空元素,而指定的集合不允许空元素(可选),或者指定的集合是空的,这个方法会抛出 NullPointerException 。
下面是说明removeAll()方法的例子。
例1 :
// Java program to demonstrate
// removeAll() method for Integer value
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception
{
try {
// Creating object of LinkedHashSet<Integer>
LinkedHashSet<Integer>
set1 = new LinkedHashSet<Integer>();
// Populating set1
set1.add(1);
set1.add(2);
set1.add(3);
set1.add(4);
set1.add(5);
// print set1
System.out.println("LinkedHashSet before "
+ "removeAll() operation : "
+ set1);
// Creating another object of LinkedHashSet<Integer>
LinkedHashSet<Integer>
set2 = new LinkedHashSet<Integer>();
set2.add(1);
set2.add(2);
set2.add(3);
// print set2
System.out.println("Collection Elements"
+ " to be removed : "
+ set2);
// Removing elements from set
// specified in set2
// using removeAll() method
set1.removeAll(set2);
// print set1
System.out.println("LinkedHashSet after "
+ "removeAll() operation : "
+ set1);
}
catch (NullPointerException e) {
System.out.println("Exception thrown : " + e);
}
}
}
输出:
LinkedHashSet before removeAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be removed : [1, 2, 3]
LinkedHashSet after removeAll() operation : [4, 5]
例2: 对于NullPointerException
// Java program to demonstrate
// removeAll() method for Integer value
import java.util.*;
public class GFG1 {
public static void main(String[] argv) throws Exception
{
try {
// Creating object of LinkedHashSet<Integer>
LinkedHashSet<Integer>
set1 = new LinkedHashSet<Integer>();
// Populating set1
set1.add(1);
set1.add(2);
set1.add(3);
set1.add(4);
set1.add(5);
// print set1
System.out.println("LinkedHashSet before "
+ "removeAll() operation : "
+ set1);
// Creating another object of LinkedHashSet<Integer>
LinkedHashSet<Integer>
set2 = null;
// print set2
System.out.println("Collection Elements"
+ " to be removed : "
+ set2);
System.out.println("\nTrying to pass "
+ "null as a specified element\n");
// Removing elements from set
// specified in set2
// using removeAll() method
set1.removeAll(set2);
// print set1
System.out.println("LinkedHashSet after "
+ "removeAll() operation : "
+ set1);
}
catch (NullPointerException e) {
System.out.println("Exception thrown : " + e);
}
}
}
输出:
LinkedHashSet before removeAll() operation : [1, 2, 3, 4, 5]
Collection Elements to be removed : null
Trying to pass null as a specified element
Exception thrown : java.lang.NullPointerException
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