Java Ints lastIndexOf() 函数

Guava的 Ints .lastIndexOf() 返回数组中目标值最后出现的索引。

语法

public static int 
  lastIndexOf(int[] array, int target)

参数

array: 一个int值的数组，可能为空。
target: 一个原始的int值。

返回值： Ints.indexOf()方法返回array[i] == target的 最大索引 i，如果不存在这样的索引，则返回 -1 。

例1 :

// Java code to show implementation of
// Guava's Ints.lastIndexOf() method
  
import com.google.common.primitives.Ints;
import java.util.Arrays;
  
class GFG {
  
    // Driver's code
    public static void main(String[] args)
    {
  
        // Creating an integer array
        int[] arr = { 1, 2, 3, 4, 3, 5, 3, 4 };
  
        int target = 3;
  
        // Using Ints.lastIndexOf() method to get the
        // index of last appearance of a given element
        // in array and return -1 if element is
        // not found in the array
        int index = Ints.lastIndexOf(arr, target);
  
        if (index != -1) {
            System.out.println("Target is present at index "
                               + index);
        }
        else {
            System.out.println("Target is not present"
                               + " in the array");
        }
    }
}

输出:

Target is present at index 6

例2 :

// Java code to show implementation of
// Guava's Ints.lastIndexOf() method
  
import com.google.common.primitives.Ints;
import java.util.Arrays;
  
class GFG {
  
    // Driver's code
    public static void main(String[] args)
    {
  
        // Creating an integer array
        int[] arr = { 3, 5, 7, 11, 13 };
  
        int target = 17;
  
        // Using Ints.lastIndexOf() method to get the
        // index of last appearance of a given element
        // in array and return -1 if element is
        // not found in the array
        int index = Ints.lastIndexOf(arr, target);
  
        if (index != -1) {
            System.out.println("Target is present at index "
                               + index);
        }
        else {
            System.out.println("Target is not present"
                               + " in the array");
        }
    }
}