Java Ints indexOf() 函数
Guava的 Ints .indexOf(int[] array, int target) 方法返回目标值在数组中 第一次 出现的索引。
语法
public static int indexOf(int[] array, int target)
参数: 该方法接受以下参数。
- array: 一个int值的数组,可能是空的。
- target: 一个原始的int值。
返回值: 本方法返回 array[i] == target
的 最小索引 i,如果不存在这样的索引,则返回 -1 。
例1 :
// Java code to show implementation of
// Guava's Ints.indexOf() method
import com.google.common.primitives.Ints;
import java.util.Arrays;
class GFG {
// Driver's code
public static void main(String[] args)
{
// Creating an integer array
int[] arr = { 1, 2, 3, 4, 3, 5 };
int target = 3;
// Using Ints.indexOf(int[] array, int target)
// method to get the index of first appearance
// of a given element in array and return -1
// if element is not found in the array
int index = Ints.indexOf(arr, target);
if (index != -1) {
System.out.println("Target is present at index "
+ index);
}
else {
System.out.println("Target is not present"
+ " in the array");
}
}
}
输出:
Target is present at index 2
例2 :
// Java code to show implementation of
// Guava's Ints.indexOf() method
import com.google.common.primitives.Ints;
import java.util.Arrays;
class GFG {
// Driver's code
public static void main(String[] args)
{
// Creating an integer array
int[] arr = { 3, 5, 7, 11, 13 };
int target = 17;
// Using Ints.indexOf(int[] array, int target) method
// to get the index of first appearance of a
// given element in array and return -1 if
// element is not found in the array
int index = Ints.indexOf(arr, target);
if (index != -1) {
System.out.println("Target is present at index "
+ index);
}
else {
System.out.println("Target is not present"
+ " in the array");
}
}
}
输出:
Target is not present in the array
参考资料: https://google.github.io/guava/releases/22.0/api/docs/com/google/common/primitives/Ints.html#indexOf-int:A-int-