Guava – Longs.contains()方法与实例

Guava的Longs类的Longs.contains()方法是用来检查一个值，即目标值是否存在于数组中。这个目标值和数组被作为该方法的参数。这个方法返回一个布尔值，说明目标值是否是

语法:

public static boolean contains(long[] array, 
                               long target)

参数: 这个方法接受两个参数。

array: 这是要搜索目标值的值数组
target: 这是要检查是否存在的长值。

返回值： 如果对于i的某个值，存在于i True 索引的值等于目标值，则该方法返回 th 异常情况。 False .

该方法不抛出任何异常。

示例1:

// Java code to show implementation of
// Guava's Longs.contains() method
  
import com.google.common.primitives.Longs;
import java.util.Arrays;
  
class GFG {
  
    // Driver's code
    public static void main(String[] args)
    {
        // Creating a long array
        long[] arr = { 5L, 4L, 3L, 2L, 1L };
  
        long target = 3L;
  
        // Using Longs.contains() method to search
        // for an element in the array. The method
        // returns true if element is found, else
        // returns false
        if (Longs.contains(arr, target))
            System.out.println("Target is present"
                               + " in the array");
        else
            System.out.println("Target is not "
                               + "present in the array");
    }
}

输出:

Target is present in the array

示例2:

// Java code to show implementation of
// Guava's Longs.contains() method
  
import com.google.common.primitives.Longs;
import java.util.Arrays;
  
class GFG {
    // Driver's code
    public static void main(String[] args)
    {
        // Creating a long array
        long[] arr = { 2L, 4L, 6L, 8L, 10L };
  
        long target = 7L;
  
        // Using Longs.contains() method to search
        // for an element in the array. The method
        // returns true if element is found, else
        // returns false
        if (Longs.contains(arr, target))
            System.out.println("Target is present"
                               + " in the array");
        else
            System.out.println("Target is not "
                               + "present in the array");
    }
}

输出: