Underscore.JS sortedIndexOf方法

_.sortedIndex(array, value, [iteratee], [context])

var _ = require('underscore');

var list = [1, 2, 4, 5, 6]
//Example: get sorted index of 3
result = _.sortedIndex(list, 3);
console.log(result)

list = [{name: 'Joe', age: 40}, {name: 'Rob', age: 60}];
//Example: get sorted index of new object
result = _.sortedIndex(list, {name: 'Julie', age: 50}, 'age' );
console.log(result)

>node tester.js

2
1