Scala 将Java的double列表转换为Scala中的Seq的程序

利用Scala中Java的toSeq方法，可以将Java的double列表转换为Scala中的序列。在此，我们需要导入Scala的JavaConversions对象，以使该转换工作，否则将会出现错误。

现在，让我们看一些示例，然后讨论它如何详细工作。

Example:1#

// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
// Creating object
object GfG
{ 
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of doubles in Java
        val list = new java.util.ArrayList[Double]()
          
        // Adding doubles to the list
        list.add(4.34)
        list.add(51.34)
        list.add(2.34)
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}

Buffer(4.34, 51.34, 2.34)

Example:2#

// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
// Creating object
object GfG
{ 
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list of doubles in Java
        val list = new java.util.ArrayList[Double]()
          
        // Adding doubles to the list
        list.add(4.15)
        list.add(4.45)
        list.add(4.11)
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
          
    }
}