Ruby 集合 compare_by_identity?函数
compare_by_identity?() 是Ruby中的一个内置方法,如果该集合将根据其元素的身份进行比较,则返回true。
语法 :s1.name.compare_by_identity?()
参数 :该函数不需要任何参数。
返回值 :如果该集合将根据其元素的身份进行比较,则返回true。
例子 1 :
#Ruby program to illustrate the
#compare_by_identity ? method
#requires the set
require "set"
s1
= Set[]
puts s1.compare_by_identity
? ()
#Add 10 to it
s1
<< 10
puts s1.compare_by_identity
? ()
s1
<< 'a'
puts s1.compare_by_identity
? ()
输出:
false
false
false
例2 :
#Ruby program to illustrate the
#compare_by_identity ? method
#requires the set
require "set"
s1
= Set[1, 2, 3]
puts s1.compare_by_identity
? ()
#Add 12 to it
s1
<< 12
puts s1.compare_by_identity
? ()
输出:
false
false
参考资料 : https://devdocs.io/ruby~2.5/set#method-i-compare_by_identity-3F