Ruby DateTime commercial()函数

DateTime#commercial() : commercial()是一个DateTime类方法，它返回一个表示给定星期日期的DateTime对象。

语法。DateTime.commercial()

参数。DateTime值

返回。一个DateTime对象，表示给定的一周日期。

例子 #1 :

# Ruby code for DateTime.commercial() method
  
# loading library
require 'date'
  
# declaring DateTime value
date_a = DateTime.commercial(2001, 5, 6, 4, 5, 6, '+7')
  
# declaring DateTime value
date_b = DateTime.commercial(2019)
  
# declaring DateTime value
date_c = DateTime.commercial(2045)
  
  
#  commercial method
puts "DateTime commercial form : #{date_a}\n\n"
  
puts "DateTime commercial form : #{date_b}\n\n"
  
puts "DateTime commercial form : #{date_c}\n\n"

输出:

DateTime commercial form : 2001-02-03T04:05:06+07:00

DateTime commercial form : 2018-12-31T00:00:00+00:00

DateTime commercial form : 2045-01-02T00:00:00+00:00

例子 #2 :

# Ruby code for DateTime.commercial() method
  
# loading library
require 'date'
  
# declaring DateTime value
date_a = DateTime.new(2034)
  
# declaring DateTime value
date_b = DateTime.parse('10 Aug 2018 04:10:06+04:30')
  
# declaring DateTime value
date_c = DateTime.new(2019, 8, 10, 4, 10, 9, '+03:00')
  
  
#  commercial method
puts "DateTime commercial form : #{date_a}\n\n"
  
puts "DateTime commercial form : #{date_b}\n\n"
  
puts "DateTime commercial form : #{date_c}\n\n"

输出:

DateTime commercial form : 2034-01-01T00:00:00+00:00

DateTime commercial form : 2018-08-10T04:10:06+04:30

DateTime commercial form : 2019-08-10T04:10:09+03:00