Ruby 数组reverse()函数

Array#reverse() : reverse() 是一个数组类的方法，它返回一个新的数组，其中包含自己的元素，顺序相反。

语法。Array.reverse()

参数。数组

返回：一个新的数组，按相反的顺序包含自己的元素。

例子 #1 :

# Ruby code for reverse() method
  
# declaring array
a = [18, 22, 33, nil, 5, 6]
  
# declaring array
b = [1, 4, 1, 1, 88, 9]
  
# declaring array
c = [18, 22, 50, 6]
  
# reverse method example
puts "reverse() method form : #{a.reverse()}\n\n"
  
puts "reverse() method form : #{b.reverse()}\n\n"
  
puts "reverse() method form : #{c.reverse()}\n\n"

输出:

reverse() method form : [6, 5, nil, 33, 22, 18]

reverse() method form : [9, 88, 1, 1, 4, 1]

reverse() method form : [6, 50, 22, 18]

例子 #2 :

# Ruby code for reverse() method
  
# declaring array
a = ["abc", "nil", "dog"]
  
# declaring array
c = ["cat", nil]
  
# declaring array
b = ["cow", nil, "dog"]
  
# reverse method example
puts "reverse() method form : #{a.reverse()}\n\n"
  
puts "reverse() method form : #{b.reverse()}\n\n"
  
puts "reverse() method form : #{c.reverse()}\n\n"

输出:

reverse() method form : ["dog", "nil", "abc"]

reverse() method form : ["dog", nil, "cow"]

reverse() method form : [nil, "cat"]