使用Python，用于将小时分钟时间转换为文本格式的程序

假设我们有两个输入：小时和分钟。我们必须以文本格式显示时间。例如 −

8:00 : 8点整
8:01 : 八点零一
8:10 : 八点十分
8:15 : 八点一刻
8:30 : 八点半
8:40 : 八点四十分（离九点还有二十分钟）
8:45 : 八点四十五分（差一刻九）
8:47 : 八点四十七分（差十三分钟九点）
8:28 : 八点二十八分

所以，如果输入为h = 9，m = 42，则输出将为十点前十八分钟

为了解决这个问题，我们将遵循以下步骤−

text: =包含30个不同数字值的文本列表，如下所示： [“one”, “two”, “three”, “four”, “five”, “six”, “seven”, “eight”,”nine”,”ten”, “eleven”, “twelve”, “thirteen”, “fourteen”, “quarter”, “sixteen”,”seventeen”, “eighteen”, “nineteen”, “twenty”, “twenty-one”,”twenty-two”, “twenty-three”, “twenty-four”, “twenty-five”,”twenty-six”, “twenty-seven”, “twenty-eight”, “twenty-nine”, “half”]
op: = 空字符串
如果m与0相同，则
- op: = text[h – 1] +“点钟”
否则，当m和30相同时，则
- op: = text[m – 1] + ‘过去’ + text[h – 1]
否则，当m和1相同时，则
- op: = text[m – 1]+ “过去” + text[h – 1] + “分”
否则，当m和15相同时，则
- op: = text[m – 1] + ‘过去’ + text[h – 1]
否则，当m – 30不为零时，则
- op: = text[m – 1] + ‘过去’ + text[h – 1] + ‘分钟’
否则，当m和45相同时，则
- op: =”离” + text[h] + “还有一刻”
否则
- op: = text[(60 – m) -1] + ‘离’ + text[h] + “还有” + “分钟”
返回op

例子

让我们看一下下面的实现，以更好地理解−

def solve(h, m):
   text=["one", "two", "three", "four", "five", "six", "seven", "eight","nine","ten", "eleven", "twelve", "thirteen", "fourteen", "quarter", "sixteen","seventeen", "eighteen", "nineteen", "twenty", "twenty-one","twenty-two", "twenty-three", "twenty-four", "twentyfive"," twenty-six", "twenty-seven", "twenty-eight","twenty-nine", "half"]

   op=""
   if (m == 0):
      op = text[h - 1] + "点钟"
   elif (m == 30):
      op = text[m - 1]+ "过去" + text[h - 1]
   elif (m == 1):
      op = text[m - 1] + "过去" + text[h - 1] + "分"
   elif (m == 15):
      op = text[m - 1]+ "过去" + text[h - 1]
   elif (m < 30):
      op = text[m - 1] + "过去" + text[h - 1] + '分钟'
   elif (m==45):
      op = "离" + text[h] + "还有一刻"
   else:
      op = text[(60 - m)-1] + '离' + text[h] + "还有" + "分钟"
   return op

h = 9
m = 42
print(solve(h, m))