PyQt5 QSpinBox – 检查它是否是活动窗口
在这篇文章中,我们将看到如何检查旋转盒是否是活动窗口。活动窗口是指包含有键盘焦点的小部件的窗口(如果该窗口没有小部件或其小部件都不接受键盘焦点,则该窗口仍有焦点)。默认情况下,这个属性是假的。
为了做到这一点,我们使用自旋盒对象的isActiveWindow方法。
语法: spin_box.isActiveWindow()
参数: 它不需要参数
返回: 它返回bool
下面是实现方法
# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
class Window(QMainWindow):
def __init__(self):
super().__init__()
# setting title
self.setWindowTitle("Python ")
# setting geometry
self.setGeometry(100, 100, 600, 400)
# calling method
self.UiComponents()
# showing all the widgets
self.show()
# method for widgets
def UiComponents(self):
# creating spin box
self.spin = QSpinBox(self)
# setting geometry to spin box
self.spin.setGeometry(100, 100, 250, 40)
# setting range to the spin box
self.spin.setRange(1, 999999)
# setting prefix to spin
self.spin.setPrefix("PREFIX ")
# setting suffix to spin
self.spin.setSuffix(" SUFFIX")
# creating a label
label = QLabel(self)
# making the label multi line
label.setWordWrap(True)
# setting geometry to the label
label.setGeometry(100, 200, 200, 60)
# checking if spin box is active window
check = self.spin.isActiveWindow()
# setting text to the label
label.setText("Active window? : " + str(check))
# create pyqt5 app
App = QApplication(sys.argv)
# create the instance of our Window
window = Window()
# start the app
sys.exit(App.exec())
输出: