如何使用MySQL查询的id、name和age三个条件来获取学生记录？

首先创建一个表 –

mysql> create table DemoTable
(
    StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
    StudentName varchar(50),
    StudentAge int
);
Query OK, 0 rows affected (0.72 sec)

使用插入命令在表中插入一些记录 –

mysql> insert into DemoTable(StudentName,StudentAge) values('Chris',21);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable(StudentName,StudentAge) values('David',23);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(StudentName,StudentAge) values('Bob',22);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable(StudentName,StudentAge) values('Carol',21);
Query OK, 1 row affected (0.30 sec)

使用select语句显示表中的所有记录 –

mysql> select *from DemoTable;

这将产生以下输出 –

+-----------+-------------+------------+
| StudentId | StudentName | StudentAge |
+-----------+-------------+------------+
|         1 | Chris       |         21 |
|         2 | David       |         23 |
|         3 | Bob         |         22 |
|         4 | Carol       |         21 |
+-----------+-------------+------------+
4 rows in set (0.00 sec)

以下是实现三个条件以获取特定记录的查询 –

mysql> select *from DemoTable where StudentId=4 and StudentName='Carol' and StudentAge=21;

这将产生以下输出 –

+-----------+-------------+------------+
| StudentId | StudentName | StudentAge |
+-----------+-------------+------------+
|         4 | Carol       |         21 |
+-----------+-------------+------------+
1 row in set (0.00 sec)

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