如何使用MySQL LIKE创建搜索系统并根据关键字显示结果？

要根据关键字显示结果，请使用LIKE运算符，如下所示的语法：

select *from yourTableName where yourColumnName LIKE '%yourValue%';

让我们先创建一个表 –

mysql> create table DemoTable812(Comments text);
Query OK, 0 rows affected (0.61 sec)

使用插入命令向表中插入一些记录 –

mysql> insert into DemoTable812 values('Good Looking');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable812 values('Awesome');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable812 values('Looking Gorgeous');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable812 values('Good Luck');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable812 values('Have a nice day');
Query OK, 1 row affected (0.21 sec)

使用select语句从表中显示所有记录 –

mysql> select *from DemoTable812;

这将产生以下输出 –

+------------------+
| Comments         |
+------------------+
| Good Looking     |
| Awesome          |
| Looking Gorgeous |
| Good Luck        |
| Have a nice day  |
+------------------+
5 rows in set (0.00 sec)

以下是使用MySQL LIKE创建搜索系统并根据关键字显示结果的查询 –

mysql> select *from DemoTable812 where Comments LIKE '%Look%';

这将产生以下输出 –

+------------------+
| Comments         |
+------------------+
| Good Looking     |
| Looking Gorgeous |
+------------------+
2 rows in set (0.00 sec)

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