如何在MySQL中选择新闻表中最近6个月的记录？

要从新闻表中选择最近6个月的记录，请使用MySQL中的date_sub()函数，因为新闻记录是按日期排列的。

语法如下 –

select *from yourTableName where yourDateTimeColumnName >= date_sub(now(),interval 6 month);

为了理解上述概念，让我们首先创建一个只有新闻ID和发布日期的NEWS表 –

mysql> create table Newstable
   -> (
   -> NewsId int,
   -> NewsDatetime datetime
   -> );
Query OK, 0 rows affected (0.66 sec)

使用insert命令在表中插入记录。查询如下 –

mysql> insert into Newstable values(101,'2018-2-10');
Query OK, 1 row affected (0.18 sec)

mysql> insert into Newstable values(102,'2018-12-10');
Query OK, 1 row affected (0.19 sec)

mysql> insert into Newstable values(103,'2018-3-14');
Query OK, 1 row affected (0.14 sec)

mysql> insert into Newstable values(104,'2018-12-12');
Query OK, 1 row affected (0.29 sec)

mysql> insert into Newstable values(105,'2018-4-21');
Query OK, 1 row affected (0.09 sec)

mysql> insert into Newstable values(106,'2018-6-30');
Query OK, 1 row affected (0.22 sec)

使用select语句显示表中的所有记录。查询如下 –

mysql> select *from Newstable;

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输出

+--------+---------------------+
| NewsId | NewsDatetime        |
+--------+---------------------+
|    101 | 2018-02-10 00:00:00 |
|    102 | 2018-12-10 00:00:00 |
|    103 | 2018-03-14 00:00:00 |
|    104 | 2018-12-12 00:00:00 |
|    105 | 2018-04-21 00:00:00 |
|    106 | 2018-06-30 00:00:00 |
+--------+---------------------+
6 rows in set (0.00 sec)

下面是从新表中选择最近6个月的查询。查询如下 –

mysql> select *from Newstable where NewsDatetime > date_sub(now(),Interval 6 month);

输出

+--------+---------------------+
| NewsId | NewsDatetime        |
+--------+---------------------+
|    102 | 2018-12-10 00:00:00 |
|    104 | 2018-12-12 00:00:00 |
|    106 | 2018-06-30 00:00:00 |
+--------+---------------------+
3 rows in set (0.00 sec)