如何从datetime列中选择MySQL日期？

使用DATE_FORMAT。 首先创建一个表 –

mysql> create table DemoTable
   (
   ShippingDate varchar(200)
    );
Query OK, 0 rows affected (0.25 sec)

使用insert命令将一些记录插入到表中 –

mysql> insert into DemoTable values('04:58 PM 10/31/2018');
Query OK, 1 row affected (0.10 sec)

mysql> insert into DemoTable values('02:30 AM 01/01/2019');
Query OK, 1 row affected (0.07 sec)

mysql> insert into DemoTable values('12:01 AM 05/03/2019');
Query OK, 1 row affected (0.06 sec)

使用select语句显示表中的所有记录 –

mysql> select *from DemoTable;

这将产生以下输出 –

+---------------------+
| ShippingDate        |
+---------------------+
| 04:58 PM 10/31/2018 |
| 02:30 AM 01/01/2019 |
| 12:01 AM 05/03/2019 |
+---------------------+
3 rows in set (0.00 sec)

以下是从datetime列中仅选择日期的查询 –

mysql> SELECT DATE_FORMAT(STR_TO_DATE(ShippingDate, '%h:%i %p %m/%d/%Y'), '%m/%d/%Y') from DemoTable;

这将产生以下仅显示日期的输出 –

+-------------------------------------------------------------------------+
| DATE_FORMAT(STR_TO_DATE(ShippingDate, '%h:%i %p %m/%d/%Y'), '%m/%d/%Y') |
+-------------------------------------------------------------------------+
| 10/31/2018                                                              |
| 01/01/2019                                                              |
| 05/03/2019                                                              |
+-------------------------------------------------------------------------+
3 rows in set (0.00 sec)

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