如何使用MySQL从同一列中选择不同的值并将它们显示在不同的列中?
使用CASE语句基于条件选择不同的值。让我们首先创建一个表 –
mysql> create table DemoTable
(
Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
Name varchar(40),
Score int
);
Query OK, 0 rows affected (0.54 sec)
使用插入命令在表中插入一些记录 –
mysql> insert into DemoTable(Name,Score) values('Chris',45);
Query OK, 1 row affected (0.24 sec)
mysql> insert into DemoTable(Name,Score) values('David',68);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(Name,Score) values('Robert',89);
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable(Name,Score) values('Bob',34);
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable(Name,Score) values('Sam',66);
Query OK, 1 row affected (0.22 sec)
使用select语句从表中显示所有记录 –
mysql> select *from DemoTable;
这将生成以下输出 –
+----+--------+-------+
| Id | Name | Score |
+----+--------+-------+
| 1 | Chris | 45 |
| 2 | David | 68 |
| 3 | Robert | 89 |
| 4 | Bob | 34 |
| 5 | Sam | 66 |
+----+--------+-------+
5 rows in set (0.00 sec)
以下是从同一列选择不同值的查询 –
mysql> select Score,
case when Score < 40 then Score end as ' Score Less than 40',
case when Score between 60 and 70 then Score end as 'Score Between 60 and 70 ',
case when Score > 80 then Score end as 'Score greater than 80'
from DemoTable;
这将生成以下输出 –
+-------+--------------------+--------------------------+-----------------------+
| Score | Score Less than 40 | Score Between 60 and 70 | Score greater than 80 |
+-------+--------------------+--------------------------+-----------------------+
| 45 | NULL | NULL | NULL |
| 68 | NULL | 68 | NULL |
| 89 | NULL | NULL | 89 |
| 34 | 34 | NULL | NULL |
| 66 | NULL | 66 | NULL |
+-------+--------------------+--------------------------+-----------------------+
5 rows in set, 1 warning (0.03 sec)
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