如何使用MySQL选择从选定日期(2010-11-04)到当前日期的查询？

首先让我们创建一个表 −

mysql> create table DemoTable
(
   Joiningdate date
);
Query OK, 0 rows affected (0.56 sec)

使用insert命令在表中插入一些记录 −

mysql> insert into DemoTable values('2010-01-01');
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable values('2010-03-31');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('2010-11-04');
Query OK, 1 row affected (0.21 sec)
mysql> insert into DemoTable values('2012-12-31');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('2019-01-03');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('2016-04-05');
Query OK, 1 row affected (0.11 sec)

使用select语句显示表中的所有记录−

mysql> select *from DemoTable;

这将产生以下输出−

+-------------+
| Joiningdate |
+-------------+
| 2010-01-01  |
| 2010-03-31  |
| 2010-11-04  |
| 2012-12-31  |
| 2019-01-03  |
| 2016-04-05  |
+-------------+
6 rows in set (0.00 sec)

以下是使用MySQL选择一个选定日期(2010-11-04)到当前日期的查询语句−

mysql> select *from DemoTable where Joiningdate >='2010-11-04' order by Joiningdate;

这将产生以下输出−

+-------------+
| Joiningdate |
+-------------+
| 2010-11-04  |
| 2012-12-31  |
| 2016-04-05  |
| 2019-01-03  |
+-------------+
4 rows in set (0.00 sec)

阅读更多：MySQL 教程