MySQL 如何从记录有员工薪水的MySQL表中获取前三个最高薪水

为此，使用LIMIT和OFFSET。首先让我们创建一个表−

mysql> create table DemoTable867(EmployeeSalary int);
Query OK, 0 rows affected (0.64 sec)

使用INSERT命令在表中插入一些记录−

mysql> insert into DemoTable867 values(63737);
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable867 values(899833);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable867 values(23644);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable867 values(89393);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable867 values(534333);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable867 values(889322);
Query OK, 1 row affected (0.08 sec)

使用SELECT语句显示表中的所有记录−

mysql> select *from DemoTable867;

这将产生以下输出 −

+----------------+
| EmployeeSalary |
+----------------+
| 63737          |
| 899833         |
| 23644          |
| 89393          |
| 534333         |
| 889322         |
+----------------+
6 rows in set (0.00 sec)

以下是获取第一高工资的查询−

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1;

这将产生以下输出 −

+----------------+
| EmployeeSalary |
+----------------+
| 899833         |
+----------------+
1 row in set (0.02 sec)

以下是获取第二高工资的查询−

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 1;

这将产生以下输出 −

+----------------+
| EmployeeSalary |
+----------------+
| 889322         |
+----------------+
1 row in set (0.00 sec)

以下是获取第三高工资的查询−

mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 2;

这将产生以下输出 −

+----------------+
| EmployeeSalary |
+----------------+
| 534333         |
+----------------+
1 row in set (0.00 sec)

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