MySQL 如何找到所有不在集合数组中的记录

为此，您可以使用NOT IN（）函数。

让我们首先创建一个表 –

mysql> create table DemoTable718 (
   Id int,
   FirstName varchar(100),
   Age int
);
Query OK, 0 rows affected (0.59 sec)

使用insert命令在表中插入一些记录-

mysql> insert into DemoTable718 values(101,'Chris',26);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable718 values(102,'Robert',24);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable718 values(103,'David',27);
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable718 values(104,'Mike',28);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable718 values(105,'Sam',23);
Query OK, 1 row affected (0.14 sec)

使用select语句显示表中的所有记录 –

mysql> select *from DemoTable718;

这将产生以下输出 –

+------+-----------+------+
| Id   | FirstName | Age  |
+------+-----------+------+
| 101  | Chris     | 26   |
| 102  | Robert    | 24   |
| 103  | David     | 27   |
| 104  | Mike      | 28   |
| 105  | Sam       | 23   |
+------+-----------+------+
5 rows in set (0.00 sec)

以下是查找所有不在集合数组中的记录的查询 –

mysql> select *from DemoTable718 where Id NOT IN('101','103','104');

这将产生以下输出 –

+------+-----------+------+
| Id   | FirstName | Age  |
+------+-----------+------+
| 102  | Robert    | 24   |
| 105  | Sam       | 23   |
+------+-----------+------+
2 rows in set (0.00 sec)

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